# An automobile company manufactures both a two wheeler (TW) and a four wheeler (FW)

## An automobile company manufactures both a two wheeler (TW) and a four wheeler (FW)

Problem Statement – An automobile company manufactures both a two wheeler (TW) and a four wheeler (FW). A company manager wants to make the production of both types of vehicle according to the given data below:

• 1st data, Total number of vehicle (two-wheeler + four-wheeler)=v
• 2nd data, Total number of wheels = W

The task is to find how many two-wheelers as well as four-wheelers need to manufacture as per the given data.

Example :

Input :

• 200  -> Value of V
• 540   -> Value of W

Output :

• TW =130 FW=70

Explanation:

130+70 = 200 vehicles

(70*4)+(130*2)= 540 wheels

Constraints :

• 2<=W
• W%2=0
• V<W

Print “INVALID INPUT” , if inputs did not meet the constraints.

The input format for testing

The candidate has to write the code to accept two positive numbers separated by a new line.

• First Input line – Accept value of V.
• Second Input line- Accept value for W.

The output format for testing

• Written program code should generate two outputs, each separated by a single space character(see the example)
• Additional messages in the output will result in the failure of test case

``````#include <bits/stdc++.h>
using namespace std;

int main ()
{
int v, w;
cin >> v >> w;
float x = ((4 * v) - w) / 2;
if ((w & 1) || w < 2 || w <= v)
{
cout << "INVALID INPUT";
return 0;
}
cout << "TW=" << x << " " << "FW=" << v - x;

}``````

``````import java.util.*;
public class Solution
{
public static void main(String[] args)
{
Scanner sc=new Scanner(System.in);
int v=sc.nextInt();
int w=sc.nextInt();
float res=((4*v)-w)/2;
if(w>=2 && (w%2==0) && v<w )
System.out.println("TW= "+(int)(res)+" FW= "+(int)(v-res));
else
System.out.println("INVALID INPUT");
}
}``````

``````v=int(input())
w=int(input())
if (w&1)==1 or w<2 or w<=v:
print("INVALID INPUT")
else:
x=((4*v) -w)//2
print("TW={0} FW={1}".format(x,v-x))``````

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